Ascii To Binary Conversion Program In 8085 Code Number 0

In this code number 0 through 9 are represented as 30 through 39 respectively and letters A through Z are represented as 41H through 5AH.

Therefore, by adding 30H we can convert number into its ASCII equivalent and by adding 37H we can convert letter to its ASCII equivalent.

First of all do ASCII-Gray conversion by Dividing the ASCII number by 2 until the quotient is 0.

Step II: Initialize count in CL 08 H Step III: Divide the number by 2 i.e.

Step IV: Decrement count Step V: Check if count 0 Step VI: If yes go to step VII else go to step III.

Ascii To Binary Conversion Program In 8085 Install From Here

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Sample Problem: (6000) H 8AH Source Program LXI H, 6200H: Initialize lookup table pointer LXI D, 6000H: Initialize source memory pointer LXI B, 7000H: Initialize destination memory pointer BACK: LDAX D: Get the number MOV L, A: A point to the 7-segment code MOV A, M: Get the 7-segment code STAX B: Store the result at destination memory location INX D: Increment source memory pointer INX B: Increment destination memory pointer MOV A, C CPI O5H: Check for last number JNZ BACK: If not repeat HLT: End of program 57.

Its not created and manipulated by a professional; But by a student like you.

Source Program: MVI D, COUNT: Initialize counter MVI B, 00: Initialize variable to store previous number MVI C, 01: Initialize variable to store current number MOV A, B:Add two numbers BACK: ADD C:Add two numbers MOV B, C: Current number is now previous number MOV C, A: Save result as a new current number DCR D: Decrement count JNZ BACK: if count 0 go to BACK HLT: Stop.

Generate a delay of 0.4 seconds Statement:Write a program to generate a delay of 0.4 sec if the crystal frequency is 5 MHz.

Calculation: In 8085, the operating frequency is half of the crystal frequency, ie.Operating frequency 52 2.5 MHz Time for one T -state Number of T-states required 1 x 106 Source Program: LXI B, count: 16 - bit count BACK: DCX B: Decrement count MOV A, C ORA B: Logically OR Band C JNZ BACK: If result is not zero repeat Arrange in DESCENDING Order Statement: Arrange an array of 8 bit unsigned no in descending order Source Program: START:MVI B, 00; Flag 0 LXI H, 4150; Count length of array MOV C, M DCR C; No.

Statement: Transfer ten bytes of data from one memory to another memory block.

Source memory block starts from memory location 2200H where as destination memory block starts from memory location 2300H.

The binary number is stored in memory location 4200H and store the square root in 4201H.

Source Program: MVI A,99H SUB E: Find the 99s complement of subtrahend INR A: Find 100s complement of subtrahend ADD D: Add minuend to 100s complement of subtrahend DAA: Adjust for BCD HLT: Terminate program execution Multiply two 2-digit BCD numbers Statement: Write an assembly language program to multiply 2 BCD numbers Source Program: MVI C, Multiplier: Load BCD multiplier MVI B, 00: Initialize counter LXI H, 0000H: Result 0000 MVI E, multiplicand: Load multiplicand MVI D, 00H: Extend to 16-bits BACK: DAD D: Result Result Multiplicand MOV A, L: Get the lower byte of the result ADI, 00H DAA: Adjust the lower byte of result to BCD.

MOV L, A: Store the lower byte of result MOV A, H: Get the higher byte of the result ACI, 00H DAA: Adjust the higher byte of the result to BCD MOV H, A: Store the higher byte of result.

MOV A, B: Increment ADI 01H: counter DAA: adjust it to BCD and MOV B,A: store it CMP C: Compare if count multiplier JNZ BACK: if not equal repeat HLT: Stop Generate and display binary up counter Statement:Write a program for displaying binary up counter.

Counter should count numbers from 00 to FFH and it should increment after every 0.5 sec.

Assume operating frequency of 8085 equal to 2MHz.

Source Program: LXI SP, 27FFH: Initialize stack pointer MVI C, OOH: Initialize counter BACK: CALL Display: Call display subroutine CALL Delay: Call delay subroutine INR C: Increment counter MOV A, C CPI OOH: Check counter is FFH JNZ BACK: If not, repeat HLT: Stop Delay Subroutine: Delay: LXI B, count: Initialize count BACK: DCX D: Decrement count MOV A, E ORA D: Logically OR D and E JNZ BACK: If result is not 0 repeat RET: Return to main program Flowchart for Source Program: Flowchart for Delay routine: Generate and display BCD up counter with frequency 1Hz Statement:Write a program for displaying BCD up counter.

Counter should count numbers from 00 to 99H and it should increment after every 1 sec.

Operating Frequency: 3MHz Flowchart for Source Program: Flowchart for Delay routine: Generate and display BCD down counter Statement:Write a program for displaying BCD down counter.

Counter should count numbers from 99 to 00 and it should increment after every 1 sec.

Operating frequency of microprocessor is 3.072 MHz.

Neglect delay for the main program.

Delay routine with error: DELAY: LXI H, N L1: DCX H JNZ L1 Sol.: 1) The fault in the above program is at instruction JNZ L1.

This condition always evaluates to be true hence loops keep on executing and hence infinite loop.

Reason for infinite looping: - The instruction DCX H decrease the HL pair count one by one but it does not affect the zero flag.

So when count reaches to OOOOH in HL pair zero flag is not affected and JNZ L1 evaluates to be true and loop continues.

Now HL again decrements below OOOOH and HL becomes FFFFH and thus execution continues.

The modification in the program is as follows: DELAY: LXI H, N:Load 16 bit count L1: DCX H: Decrement count MOV A, L ORA H: logically OR Hand L JNZ L1: If result is not 0 repeat PROGRAMS IN CODE CONVERSION 2-Digit BCD to binary conversion.

Divide by 64H (Decimal 100) 8AH64H Quotient 1, Remainder 26H 26H 2.26H OAH (Decimal 10).

Divide by OAH (Decimal 10) 26HOAH Quotient 3, Remainder O8H OSH 3.